https://leetcode.com/problems/find-minimum-time-to-reach-last-room-i

medium/find_minimum_time_to_reach_last_room_i.py

@@ -0,0 +1,28 @@
+# https://leetcode.com/problems/find-minimum-time-to-reach-last-room-i
+
+import heapq
+from typing import List, Tuple
+
+class Solution:
+    def minTimeToReach(self, moveTime: List[List[int]]) -> int:
+        n, m = len(moveTime), len(moveTime[0])
+        dirs: List[Tuple[int, int]] = [(-1, 0), (1, 0), (0, -1), (0, 1)]
+        min_time = [[float('inf')] * m for _ in range(n)]
+        min_time[0][0] = 0
+        heap: List[Tuple[int, int, int]] = [(0, 0, 0)]
+
+        while heap:
+            curr_time, y, x = heapq.heappop(heap)
+            if (y, x) == (n - 1, m - 1):
+                return curr_time
+            if curr_time > min_time[y][x]:
+                continue
+            for dy, dx in dirs:
+                ny, nx = y + dy, x + dx
+                if 0 <= ny < n and 0 <= nx < m:
+                    start_time = max(curr_time, moveTime[ny][nx])
+                    arrival_time = start_time + 1
+                    if arrival_time < min_time[ny][nx]:
+                        min_time[ny][nx] = arrival_time
+                        heapq.heappush(heap, (arrival_time, ny, nx))
+        return -1