diff --git a/easy/minimum_number_of_operations_to_make_elements_in_array_distinct.py b/easy/minimum_number_of_operations_to_make_elements_in_array_distinct.py
new file mode 100644
index 0000000..12b75fa
--- /dev/null
+++ b/easy/minimum_number_of_operations_to_make_elements_in_array_distinct.py
@@ -0,0 +1,26 @@
+# https://leetcode.com/problems/minimum-number-of-operations-to-make-elements-in-array-distinct
+
+from typing import List
+
+class Solution:
+    def minimumOperations(self, nums: List[int]) -> int:
+        result = 0
+        cnt = {}
+        left, right = 0, 0
+        while right < len(nums):
+            curr_num = nums[right]
+            cnt[curr_num] = cnt.get(curr_num, 0) + 1
+            while cnt[curr_num] > 1:
+                result += 1
+                pops = len(nums) - left
+                if pops > 3:
+                    pops = 3
+                for _ in range(pops):
+                    if left <= right:
+                        cnt[nums[left]] -= 1
+                    left += 1
+                if left > right:
+                    right = left - 1
+            right += 1
+        return result
+