diff --git a/easy/divide-an-array-into-subarrays-with-minimum-cost-i.py b/easy/divide-an-array-into-subarrays-with-minimum-cost-i.py
new file mode 100644
index 0000000..ae92b9a
--- /dev/null
+++ b/easy/divide-an-array-into-subarrays-with-minimum-cost-i.py
@@ -0,0 +1,7 @@
+# https://leetcode.com/problems/divide-an-array-into-subarrays-with-minimum-cost-i
+
+class Solution:
+    def minimumCost(self, nums: List[int]) -> int:
+        first = nums[0]
+        rest = sorted(nums[1:])
+        return first + rest[0] + rest[1]
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